Log message #4212913

# At Username Text
# Nov 9th, 03:12 francisdoydora nevermind, figured it out :slightly_smiling_face:
# Nov 9th, 02:52 francisdoydora good morning everyone :slightly_smiling_face: ```$this->Auth->identify()``` fails when I put it in a Cell. anyway this can be fixed? error returned is ```Error: Method App\View\Cell\SwitchSidebarCell::__toString() must not throw an exception, caught Error: Could not render cell - Call to a member function identify() on null [/var/www/html/juniorhigh/src/View/Cell/SwitchSidebarCell.php, line 39]```
# Nov 8th, 21:09 sdevore > You can use the second parameter of Router::connect() to provide any routing parameters that are composed of the default values of the route: ``` Router::connect( '/government', array('controller' => 'pages', 'action' => 'display', 5) ); ```
# Nov 8th, 21:06 ricksaccous might need the double star i dunno
# Nov 8th, 21:06 ricksaccous ie just write the link using controller/action params but in routes make it route to /contact/*
# Nov 8th, 21:05 ricksaccous why aren't you using routes to handle this for you
# Nov 8th, 20:56 devito if you use the string I would need to build the query param and concat it it would seem.
# Nov 8th, 20:50 sdevore well you can always just use the string you want. Although is is a bit limiting. Let me look at another project here in a little bit and see if I did anything specific in that project because I am pretty sure I have handled in it differently
# Nov 8th, 20:17 devito i am also using query string params other wise I would just specify the url as a string
# Nov 8th, 20:16 devito got a cake2 html helper question. When using the link function and specifying a controller and action, is there a way to have the url go to the named route declaration instead of the controller/action route? like just go to /contact instead of /pages/contact ?
# Nov 8th, 18:39 samuel.assuncao @amanfulgence what youi want to do specifcally
# Nov 8th, 17:49 amanfulgence help me how create and use middelware
# Nov 8th, 17:18 samuel.assuncao Someone got a idea ?
# Nov 8th, 17:18 slackebot1 associations too, I do not see any example on documentation how i can do that with the cake ORM
# Nov 8th, 17:18 slackebot1 'Plants' ]); But Instead of getting the actual saved value from my table Purchase, I need get the data from the tables from a certain date. Sales Purchases to get volume_vendido -> created date and filter it to the $date(which is YYYY-MM-DD already) I also need the same for Purchases_Transfers (which is volume_transferido) and Purchase_Devolutions (which is volume_devolvido) So I need a where condition which will filter the
# Nov 8th, 17:18 samuel.assuncao $purchases = TableRegistry::get('Purchases')->find() ->where([ 'data_compra <=' => $date, 'volume_comprado + volume_transferido - volume_devolvido - volume_vendido > 0' ]) //certo ->matching('Plants') ->orderAsc('Plants.razao_social') ->orderAsc('Purchases.created') ->contain([ 'Distributors',
# Nov 8th, 17:18 samuel.assuncao Hi guys!
# Nov 8th, 12:51 dev.cyrusjayson and more <3
# Nov 8th, 12:50 dev.cyrusjayson more <3 here
# Nov 8th, 12:47 dev.cyrusjayson oh!
# Nov 8th, 12:46 frank @dev.cyrusjayson Yeah, it’s just because it’s looking in the namespace of your controller when you don’t define it at the top
# Nov 8th, 12:43 dev.cyrusjayson that is the response
# Nov 8th, 12:43 frank @dev.cyrusjayson use Cake\ORM\Query; at the top
# Nov 8th, 12:43 dev.cyrusjayson I get this error ``` [TypeError] Argument 1 passed to App\Controller\FruitsController::App\Controller\{closure}() must be an instance of App\Controller\Query, instance of Cake\ORM\Query given, called in ...```
# Nov 8th, 12:40 frank @dev.cyrusjayson This is what I mean, does this give the error also? ``` $fruits = $this->Fruits->find('all') ->contain(['GaveFruits' => function (Query $q) { return $q ->select(['id', 'name']) ->where(['user_id' => 1]); }]); ```
# Nov 8th, 12:37 frank @dev.cyrusjayson Wait, so with the `=>` it gave that as well?
# Nov 8th, 12:35 dev.cyrusjayson ‘Illegal offset type in isset or empty’
# Nov 8th, 12:32 frank @dev.cyrusjayson Okay, yeah that should work. What did the internal server error say, did it provide any context?
# Nov 8th, 12:31 dev.cyrusjayson here
# Nov 8th, 12:30 dev.cyrusjayson gave_fruits, sorry not in the screenshot
# Nov 8th, 12:29 frank @dev.cyrusjayson In which table is the user_id?
# Nov 8th, 12:24 dev.cyrusjayson this is the models
# Nov 8th, 12:22 dev.cyrusjayson following this is not helping https://book.cakephp.org/3/en/orm/retrieving-data-and-resultsets.html#passing-conditions-to-contain
# Nov 8th, 12:20 dev.cyrusjayson An Internal Server Error Occurred
# Nov 8th, 12:19 dev.cyrusjayson @frank I got internal error this is only thing is working but I want to filter the GaveFruits by user_id so I can get specific only ```$fruits = $this->Fruits->find('all') ->contain(['GaveFruits']);```
# Nov 8th, 12:16 frank @dev.cyrusjayson Could you try `'GaveFruits' => function ….` instead of `'GaveFruits', function ….` (arrow vs comma)
# Nov 8th, 12:08 slackebot1 [CORE/src/ORM/EagerLoader.php, line 410]``` but if I remove the ->where([‘user_id’ => 1]) everything is working so I think the problem is in ->where but based on the documentation, I am fopllowing it correctly
# Nov 8th, 12:08 dev.cyrusjayson I have this query ``` $fruits = $this->Fruits->find('all') ->contain(['GaveFruits',function (Query $q){ return $q ->select(['id', 'name']) ->where(['user_id' => 1]); }]); ``` and I get this error ```Warning (2): Illegal offset type in isset or empty
# Nov 8th, 12:01 pieceof whoami
# Nov 8th, 11:01 dev.cyrusjayson @frank noted on that. thanks
# Nov 8th, 10:59 frank @dev.cyrusjayson You can remove the foreignKey from the association definition. As you’re following the conventions Cake will know to use user_id for Users.